


if(...);?


#include <stdio.h>
int main(int argc, char **argv) {
    if(argc < 2);
    {
        fprintf(stderr, "Usage: program PARAM\n");
        return 1;
    }
    return 0;
}$ gcc -Wall -Wextra a.c
a.c: In function βmainβ:
a.c:4:14: warning: suggest braces around empty body in an βifβ statement [-Wempty-body]
    4 |  if(argc < 2);
      |              ^
a.c:4:2: warning: this βifβ clause does not guard... [-Wmisleading-indentation]
    4 |  if(argc < 2);
      |  ^~
a.c:5:2: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the βifβ
    5 |  {
      |  ^
a.c:3:27: warning: unused parameter βargvβ [-Wunused-parameter]
    3 | int main(int argc, char **argv) {
      |                    ~~~~~~~^~~~$ clang -Wall -Wextra a.c
a.c:4:14: warning: if statement has empty body [-Wempty-body]
        if(argc < 2);
                    ^
a.c:4:14: note: put the semicolon on a separate line to silence this warning
a.c:3:27: warning: unused parameter 'argv' [-Wunused-parameter]
int main(int argc, char **argv) {
                          ^
2 warnings generated.




MAX_CLIENTS=64,
    MAX_PLAYERS=16,










if abs(force) >= 5:
  do_stuff()
why does it not work? Oh right