basically need to calculate this: we got 5 players, 9 rounds, each round 1 player is assigned as a murderer, the question is: what is the probability that 1 particular player is not the murderer 9 rounds in a row
Well whats the chance that a player doesent get assigned murderer in one row? -> 4/5th
Now he needs to have that chance happen in 1st round AND 2nd AND 3rd.... And in probability if u combine things with and u gotta multiplicate (if u combine with or u gotta summate)
So u have 4/5 * 4/5 * 4/5.... Nine times so u end up with (4/5)^9
But that problem makes no sense tbh cause if someone is assigned murderer already u wouldnt assigne him again cz he already is... And with 9 rounds u would just assigne everyone murder after round 5 already lol
16:27
But i guess math questions don't have to make sense as long as u can calc something(edited)
(edited)
2
= in rainbow
2
2
